4x*6x/99-5=2

Solution for 4x*6x/99-5=2 equation:

4x*6x/99-5=2

We move all terms to the left:

4x*6x/99-5-(2)=0

We add all the numbers together, and all the variables

4x*6x/99-7=0

We multiply all the terms by the denominator


4x*6x-7*99=0

We add all the numbers together, and all the variables

4x*6x-693=0

Wy multiply elements

24x^2-693=0

a = 24; b = 0; c = -693;
Δ = b2-4ac
Δ = 02-4·24·(-693)
Δ = 66528
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{66528}=\sqrt{144*462}=\sqrt{144}*\sqrt{462}=12\sqrt{462}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{462}}{2*24}=\frac{0-12\sqrt{462}}{48}
=-\frac{12\sqrt{462}}{48}
=-\frac{\sqrt{462}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{462}}{2*24}=\frac{0+12\sqrt{462}}{48}
=\frac{12\sqrt{462}}{48}
=\frac{\sqrt{462}}{4}
$