4x+(1/2x+5)=50

Solution for 4x+(1/2x+5)=50 equation:

4x+(1/2x+5)=50

We move all terms to the left:

4x+(1/2x+5)-(50)=0


Domain of the equation: 2x+5)!=0

x∈R


We get rid of parentheses

4x+1/2x+5-50=0

We multiply all the terms by the denominator


4x*2x+5*2x-50*2x+1=0

Wy multiply elements

8x^2+10x-100x+1=0

We add all the numbers together, and all the variables

8x^2-90x+1=0

a = 8; b = -90; c = +1;
Δ = b2-4ac
Δ = -902-4·8·1
Δ = 8068
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8068}=\sqrt{4*2017}=\sqrt{4}*\sqrt{2017}=2\sqrt{2017}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-90)-2\sqrt{2017}}{2*8}=\frac{90-2\sqrt{2017}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-90)+2\sqrt{2017}}{2*8}=\frac{90+2\sqrt{2017}}{16}
$