4x+(3+3x)=50

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Solution for 4x+(3+3x)=50 equation: 



4x+(3+3x)=50

We move all terms to the left:

4x+(3+3x)-(50)=0

We add all the numbers together, and all the variables

4x+(3x+3)-50=0

We get rid of parentheses

4x+3x+3-50=0

We add all the numbers together, and all the variables

7x-47=0

We move all terms containing x to the left, all other terms to the right

7x=47

x=47/7

x=6+5/7

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