4x+(3/4)x=29

Solution for 4x+(3/4)x=29 equation:

4x+(3/4)x=29

We move all terms to the left:

4x+(3/4)x-(29)=0


Domain of the equation: 4)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

4x+(+3/4)x-29=0

We multiply parentheses

3x^2+4x-29=0

a = 3; b = 4; c = -29;
Δ = b2-4ac
Δ = 42-4·3·(-29)
Δ = 364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{364}=\sqrt{4*91}=\sqrt{4}*\sqrt{91}=2\sqrt{91}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2\sqrt{91}}{2*3}=\frac{-4-2\sqrt{91}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2\sqrt{91}}{2*3}=\frac{-4+2\sqrt{91}}{6}
$