4x+(3x+3)+4x+(3x+3)=(7x-2)+(7x-2)+(2x+4)

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Solution for 4x+(3x+3)+4x+(3x+3)=(7x-2)+(7x-2)+(2x+4) equation: 



4x+(3x+3)+4x+(3x+3)=(7x-2)+(7x-2)+(2x+4)

We move all terms to the left:

4x+(3x+3)+4x+(3x+3)-((7x-2)+(7x-2)+(2x+4))=0

We add all the numbers together, and all the variables

8x+(3x+3)+(3x+3)-((7x-2)+(7x-2)+(2x+4))=0

We get rid of parentheses

8x+3x+3x-((7x-2)+(7x-2)+(2x+4))+3+3=0



We calculate terms in parentheses: -((7x-2)+(7x-2)+(2x+4)), so:

(7x-2)+(7x-2)+(2x+4)

We get rid of parentheses

7x+7x+2x-2-2+4

We add all the numbers together, and all the variables

16x

Back to the equation:

-(16x)



We add all the numbers together, and all the variables

-2x+6=0

We move all terms containing x to the left, all other terms to the right

-2x=-6

x=-6/-2

x=+3

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