4x+(4x-12)=96

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Solution for 4x+(4x-12)=96 equation: 



4x+(4x-12)=96

We move all terms to the left:

4x+(4x-12)-(96)=0

We get rid of parentheses

4x+4x-12-96=0

We add all the numbers together, and all the variables

8x-108=0

We move all terms containing x to the left, all other terms to the right

8x=108

x=108/8

x=13+1/2

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