4x+(4x-5)=10-(2x-5)

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Solution for 4x+(4x-5)=10-(2x-5) equation: 



4x+(4x-5)=10-(2x-5)

We move all terms to the left:

4x+(4x-5)-(10-(2x-5))=0

We get rid of parentheses

4x+4x-(10-(2x-5))-5=0



We calculate terms in parentheses: -(10-(2x-5)), so:

10-(2x-5)

determiningTheFunctionDomain
-(2x-5)+10

We get rid of parentheses

-2x+5+10

We add all the numbers together, and all the variables

-2x+15

Back to the equation:

-(-2x+15)



We add all the numbers together, and all the variables

8x-(-2x+15)-5=0

We get rid of parentheses

8x+2x-15-5=0

We add all the numbers together, and all the variables

10x-20=0

We move all terms containing x to the left, all other terms to the right

10x=20

x=20/10

x=2

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