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4x+(5x+1)=2(3x-2)-5
We move all terms to the left:
4x+(5x+1)-(2(3x-2)-5)=0
We get rid of parentheses
4x+5x-(2(3x-2)-5)+1=0
We calculate terms in parentheses: -(2(3x-2)-5), so:We add all the numbers together, and all the variables
2(3x-2)-5
We multiply parentheses
6x-4-5
We add all the numbers together, and all the variables
6x-9
Back to the equation:
-(6x-9)
9x-(6x-9)+1=0
We get rid of parentheses
9x-6x+9+1=0
We add all the numbers together, and all the variables
3x+10=0
We move all terms containing x to the left, all other terms to the right
3x=-10
x=-10/3
x=-3+1/3
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