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4x+(x-3)=2x-(7x+8)
We move all terms to the left:
4x+(x-3)-(2x-(7x+8))=0
We get rid of parentheses
4x+x-(2x-(7x+8))-3=0
We calculate terms in parentheses: -(2x-(7x+8)), so:We add all the numbers together, and all the variables
2x-(7x+8)
We get rid of parentheses
2x-7x-8
We add all the numbers together, and all the variables
-5x-8
Back to the equation:
-(-5x-8)
5x-(-5x-8)-3=0
We get rid of parentheses
5x+5x+8-3=0
We add all the numbers together, and all the variables
10x+5=0
We move all terms containing x to the left, all other terms to the right
10x=-5
x=-5/10
x=-1/2
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