4x+-8=2(x+-3)

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Solution for 4x+-8=2(x+-3) equation: 



4x+-8=2(x+-3)

We move all terms to the left:

4x+-8-(2(x+-3))=0

We add all the numbers together, and all the variables

4x-(2(x-3))-8+=0

We add all the numbers together, and all the variables

4x-(2(x-3))=0



We calculate terms in parentheses: -(2(x-3)), so:

2(x-3)

We multiply parentheses

2x-6

Back to the equation:

-(2x-6)



We get rid of parentheses

4x-2x+6=0

We add all the numbers together, and all the variables

2x+6=0

We move all terms containing x to the left, all other terms to the right

2x=-6

x=-6/2

x=-3

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