4x+10=-5((-4/5)x+52)+280

Solution for 4x+10=-5((-4/5)x+52)+280 equation:

4x+10=-5((-4/5)x+52)+280

We move all terms to the left:

4x+10-(-5((-4/5)x+52)+280)=0


Domain of the equation: 5)x+52)+280)!=0

x!=0/1

x!=0

x∈R


We multiply all the terms by the denominator


4x*5)x+52)+280)-(-5((+10*5)x+52)+280)-4=0

We add all the numbers together, and all the variables

4x*5)x+52)+280)-(-5(50x+52)+280)-4=0

Wy multiply elements

20x^2=0

a = 20; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·20·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{40}=0$