4x+10y=200;6x+5y=200

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Solution for 4x+10y=200;6x+5y=200 system of equations: 


  • /| 4*x+10*y-200 = 0| 6*x+5*y-200 = 0
  • We try to solve the equation: 4*x+10*y-200 = 0
  • 4*x+10*y-200 = 0 // - 4*x-200
  • 10*y = -(4*x-200) // : 10
  • y = (-(4*x-200))/10
  • y = (200-(4*x))/10
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| 5*((200-(4*x))/10)+6*x-200 = 0| y = (200-(4*x))/10
  • (5*(200-4*x))/10+6*x-200 = 0
  • 4*x-200+100 = 0
  • 4*x-100 = 0
  • 4*x-100 = 0 // + 100
  • 4*x = 100 // : 4
  • x = 100/4
  • x = 25
  • We insert the solution into one of the initial equations of our system of equations
  • For y = (200-(4*x))/10: 
  • y = (200-(4*25))/10
  • y = (200-100)/10
  • y = 100/10
  • y = 10
  • We get a system of equations:
  • /| y = 10| x = 25

 

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