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4x+11x*11x=22
We move all terms to the left:
4x+11x*11x-(22)=0
Wy multiply elements
121x^2+4x-22=0
a = 121; b = 4; c = -22;
Δ = b2-4ac
Δ = 42-4·121·(-22)
Δ = 10664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{10664}=\sqrt{4*2666}=\sqrt{4}*\sqrt{2666}=2\sqrt{2666}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2\sqrt{2666}}{2*121}=\frac{-4-2\sqrt{2666}}{242} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2\sqrt{2666}}{2*121}=\frac{-4+2\sqrt{2666}}{242} $
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