4x+12+3(2x-1)=4x+28-(2x-8)+5

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Solution for 4x+12+3(2x-1)=4x+28-(2x-8)+5 equation: 



4x+12+3(2x-1)=4x+28-(2x-8)+5

We move all terms to the left:

4x+12+3(2x-1)-(4x+28-(2x-8)+5)=0

We multiply parentheses

4x+6x-(4x+28-(2x-8)+5)-3+12=0



We calculate terms in parentheses: -(4x+28-(2x-8)+5), so:

4x+28-(2x-8)+5

determiningTheFunctionDomain
4x-(2x-8)+28+5

We add all the numbers together, and all the variables

4x-(2x-8)+33

We get rid of parentheses

4x-2x+8+33

We add all the numbers together, and all the variables

2x+41

Back to the equation:

-(2x+41)



We add all the numbers together, and all the variables

10x-(2x+41)+9=0

We get rid of parentheses

10x-2x-41+9=0

We add all the numbers together, and all the variables

8x-32=0

We move all terms containing x to the left, all other terms to the right

8x=32

x=32/8

x=4

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