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4x+12-2x=2(x-5)-5
We move all terms to the left:
4x+12-2x-(2(x-5)-5)=0
We add all the numbers together, and all the variables
2x-(2(x-5)-5)+12=0
We calculate terms in parentheses: -(2(x-5)-5), so:We get rid of parentheses
2(x-5)-5
We multiply parentheses
2x-10-5
We add all the numbers together, and all the variables
2x-15
Back to the equation:
-(2x-15)
2x-2x+15+12=0
We add all the numbers together, and all the variables
27!=0
There is no solution for this equation
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