4x+12-4=8/2x+8

Solution for 4x+12-4=8/2x+8 equation:

4x+12-4=8/2x+8

We move all terms to the left:

4x+12-4-(8/2x+8)=0


Domain of the equation: 2x+8)!=0

x∈R


We add all the numbers together, and all the variables

4x-(8/2x+8)+8=0

We get rid of parentheses

4x-8/2x-8+8=0

We multiply all the terms by the denominator


4x*2x-8*2x+8*2x-8=0

Wy multiply elements

8x^2-16x+16x-8=0

We add all the numbers together, and all the variables

8x^2-8=0

a = 8; b = 0; c = -8;
Δ = b2-4ac
Δ = 02-4·8·(-8)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16}{2*8}=\frac{-16}{16}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16}{2*8}=\frac{16}{16}
=1
$