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4x+12/4=4(3+x)/4
We move all terms to the left:
4x+12/4-(4(3+x)/4)=0
We add all the numbers together, and all the variables
4x-(4(x+3)/4)+12/4=0
We add all the numbers together, and all the variables
4x-(4(x+3)/4)+3=0
We multiply all the terms by the denominator
4x*4)-(4(x+3)+3*4)=0
We add all the numbers together, and all the variables
4x*4)-(4(x+3)=0
Wy multiply elements
16x^2=0
a = 16; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·16·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{32}=0$
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