4x+12=2(2x+6)4x+12=2(2x+6)

Solution for 4x+12=2(2x+6)4x+12=2(2x+6) equation:

4x+12=2(2x+6)4x+12=2(2x+6)

We move all terms to the left:

4x+12-(2(2x+6)4x+12)=0


We calculate terms in parentheses: -(2(2x+6)4x+12), so:

2(2x+6)4x+12

We multiply parentheses

16x^2+48x+12

Back to the equation:

-(16x^2+48x+12)


We get rid of parentheses

-16x^2+4x-48x-12+12=0

We add all the numbers together, and all the variables

-16x^2-44x=0

a = -16; b = -44; c = 0;
Δ = b2-4ac
Δ = -442-4·(-16)·0
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-44}{2*-16}=\frac{0}{-32}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+44}{2*-16}=\frac{88}{-32}
=-2+3/4
$