4x+13-(2x-(4(x-3))-5)=2(x-6)

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Solution for 4x+13-(2x-(4(x-3))-5)=2(x-6) equation: 



4x+13-(2x-(4(x-3))-5)=2(x-6)

We move all terms to the left:

4x+13-(2x-(4(x-3))-5)-(2(x-6))=0



We calculate terms in parentheses: -(2x-(4(x-3))-5), so:

2x-(4(x-3))-5



We calculate terms in parentheses: -(4(x-3)), so:

4(x-3)

We multiply parentheses

4x-12

Back to the equation:

-(4x-12)



We get rid of parentheses

2x-4x+12-5

We add all the numbers together, and all the variables

-2x+7

Back to the equation:

-(-2x+7)





We calculate terms in parentheses: -(2(x-6)), so:

2(x-6)

We multiply parentheses

2x-12

Back to the equation:

-(2x-12)



We get rid of parentheses

4x+2x-2x-7+12+13=0

We add all the numbers together, and all the variables

4x+18=0

We move all terms containing x to the left, all other terms to the right

4x=-18

x=-18/4

x=-4+1/2

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