4x+1=(2x+1)+(x+3)

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Solution for 4x+1=(2x+1)+(x+3) equation: 



4x+1=(2x+1)+(x+3)

We move all terms to the left:

4x+1-((2x+1)+(x+3))=0



We calculate terms in parentheses: -((2x+1)+(x+3)), so:

(2x+1)+(x+3)

We get rid of parentheses

2x+x+1+3

We add all the numbers together, and all the variables

3x+4

Back to the equation:

-(3x+4)



We get rid of parentheses

4x-3x-4+1=0

We add all the numbers together, and all the variables

x-3=0

We move all terms containing x to the left, all other terms to the right

x=3

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