4x+2(2x-3)=8(x+1)

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Solution for 4x+2(2x-3)=8(x+1) equation: 



4x+2(2x-3)=8(x+1)

We move all terms to the left:

4x+2(2x-3)-(8(x+1))=0

We multiply parentheses

4x+4x-(8(x+1))-6=0



We calculate terms in parentheses: -(8(x+1)), so:

8(x+1)

We multiply parentheses

8x+8

Back to the equation:

-(8x+8)



We add all the numbers together, and all the variables

8x-(8x+8)-6=0

We get rid of parentheses

8x-8x-8-6=0

We add all the numbers together, and all the variables

-14!=0

There is no solution for this equation

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