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4x+2(2x-3)=8(x-1)
We move all terms to the left:
4x+2(2x-3)-(8(x-1))=0
We multiply parentheses
4x+4x-(8(x-1))-6=0
We calculate terms in parentheses: -(8(x-1)), so:We add all the numbers together, and all the variables
8(x-1)
We multiply parentheses
8x-8
Back to the equation:
-(8x-8)
8x-(8x-8)-6=0
We get rid of parentheses
8x-8x+8-6=0
We add all the numbers together, and all the variables
2!=0
There is no solution for this equation
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