4x+2(32-x)=68

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Solution for 4x+2(32-x)=68 equation: 



4x+2(32-x)=68

We move all terms to the left:

4x+2(32-x)-(68)=0

We add all the numbers together, and all the variables

4x+2(-1x+32)-68=0

We multiply parentheses

4x-2x+64-68=0

We add all the numbers together, and all the variables

2x-4=0

We move all terms containing x to the left, all other terms to the right

2x=4

x=4/2

x=2

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