4x+2(3x+1)=6(2x-1)

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Solution for 4x+2(3x+1)=6(2x-1) equation:



4x+2(3x+1)=6(2x-1)
We move all terms to the left:
4x+2(3x+1)-(6(2x-1))=0
We multiply parentheses
4x+6x-(6(2x-1))+2=0
We calculate terms in parentheses: -(6(2x-1)), so:
6(2x-1)
We multiply parentheses
12x-6
Back to the equation:
-(12x-6)
We add all the numbers together, and all the variables
10x-(12x-6)+2=0
We get rid of parentheses
10x-12x+6+2=0
We add all the numbers together, and all the variables
-2x+8=0
We move all terms containing x to the left, all other terms to the right
-2x=-8
x=-8/-2
x=+4

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