4x+2(3x-1)=68

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Solution for 4x+2(3x-1)=68 equation: 



4x+2(3x-1)=68

We move all terms to the left:

4x+2(3x-1)-(68)=0

We multiply parentheses

4x+6x-2-68=0

We add all the numbers together, and all the variables

10x-70=0

We move all terms containing x to the left, all other terms to the right

10x=70

x=70/10

x=7

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