4x+2(3x-2)=16

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Solution for 4x+2(3x-2)=16 equation: 



4x+2(3x-2)=16

We move all terms to the left:

4x+2(3x-2)-(16)=0

We multiply parentheses

4x+6x-4-16=0

We add all the numbers together, and all the variables

10x-20=0

We move all terms containing x to the left, all other terms to the right

10x=20

x=20/10

x=2

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