4x+2(3x-2)=2-6(x+2)

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Solution for 4x+2(3x-2)=2-6(x+2) equation: 



4x+2(3x-2)=2-6(x+2)

We move all terms to the left:

4x+2(3x-2)-(2-6(x+2))=0

We multiply parentheses

4x+6x-(2-6(x+2))-4=0



We calculate terms in parentheses: -(2-6(x+2)), so:

2-6(x+2)

determiningTheFunctionDomain
-6(x+2)+2

We multiply parentheses

-6x-12+2

We add all the numbers together, and all the variables

-6x-10

Back to the equation:

-(-6x-10)



We add all the numbers together, and all the variables

10x-(-6x-10)-4=0

We get rid of parentheses

10x+6x+10-4=0

We add all the numbers together, and all the variables

16x+6=0

We move all terms containing x to the left, all other terms to the right

16x=-6

x=-6/16

x=-3/8

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