4x+2(64-x)=160

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Solution for 4x+2(64-x)=160 equation: 



4x+2(64-x)=160

We move all terms to the left:

4x+2(64-x)-(160)=0

We add all the numbers together, and all the variables

4x+2(-1x+64)-160=0

We multiply parentheses

4x-2x+128-160=0

We add all the numbers together, and all the variables

2x-32=0

We move all terms containing x to the left, all other terms to the right

2x=32

x=32/2

x=16

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