4x+2(x+1)=4(x-3)

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Solution for 4x+2(x+1)=4(x-3) equation: 



4x+2(x+1)=4(x-3)

We move all terms to the left:

4x+2(x+1)-(4(x-3))=0

We multiply parentheses

4x+2x-(4(x-3))+2=0



We calculate terms in parentheses: -(4(x-3)), so:

4(x-3)

We multiply parentheses

4x-12

Back to the equation:

-(4x-12)



We add all the numbers together, and all the variables

6x-(4x-12)+2=0

We get rid of parentheses

6x-4x+12+2=0

We add all the numbers together, and all the variables

2x+14=0

We move all terms containing x to the left, all other terms to the right

2x=-14

x=-14/2

x=-7

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