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4x+2(x-2)+10=8x-2(2x+3)
We move all terms to the left:
4x+2(x-2)+10-(8x-2(2x+3))=0
We multiply parentheses
4x+2x-(8x-2(2x+3))-4+10=0
We calculate terms in parentheses: -(8x-2(2x+3)), so:We add all the numbers together, and all the variables
8x-2(2x+3)
We multiply parentheses
8x-4x-6
We add all the numbers together, and all the variables
4x-6
Back to the equation:
-(4x-6)
6x-(4x-6)+6=0
We get rid of parentheses
6x-4x+6+6=0
We add all the numbers together, and all the variables
2x+12=0
We move all terms containing x to the left, all other terms to the right
2x=-12
x=-12/2
x=-6
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