4x+2(x-3)+4=16

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Solution for 4x+2(x-3)+4=16 equation: 



4x+2(x-3)+4=16

We move all terms to the left:

4x+2(x-3)+4-(16)=0

We add all the numbers together, and all the variables

4x+2(x-3)-12=0

We multiply parentheses

4x+2x-6-12=0

We add all the numbers together, and all the variables

6x-18=0

We move all terms containing x to the left, all other terms to the right

6x=18

x=18/6

x=3

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