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4x+2(x-3)=2(x-2)+3x
We move all terms to the left:
4x+2(x-3)-(2(x-2)+3x)=0
We multiply parentheses
4x+2x-(2(x-2)+3x)-6=0
We calculate terms in parentheses: -(2(x-2)+3x), so:We add all the numbers together, and all the variables
2(x-2)+3x
We add all the numbers together, and all the variables
3x+2(x-2)
We multiply parentheses
3x+2x-4
We add all the numbers together, and all the variables
5x-4
Back to the equation:
-(5x-4)
6x-(5x-4)-6=0
We get rid of parentheses
6x-5x+4-6=0
We add all the numbers together, and all the variables
x-2=0
We move all terms containing x to the left, all other terms to the right
x=2
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