4x+2(x-3)=3(x+2)-12+3x

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Solution for 4x+2(x-3)=3(x+2)-12+3x equation: 



4x+2(x-3)=3(x+2)-12+3x

We move all terms to the left:

4x+2(x-3)-(3(x+2)-12+3x)=0

We multiply parentheses

4x+2x-(3(x+2)-12+3x)-6=0



We calculate terms in parentheses: -(3(x+2)-12+3x), so:

3(x+2)-12+3x

determiningTheFunctionDomain
3(x+2)+3x-12

We add all the numbers together, and all the variables

3x+3(x+2)-12

We multiply parentheses

3x+3x+6-12

We add all the numbers together, and all the variables

6x-6

Back to the equation:

-(6x-6)



We add all the numbers together, and all the variables

6x-(6x-6)-6=0

We get rid of parentheses

6x-6x+6-6=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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