4x+2(x-3)=3x+x=12

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Solution for 4x+2(x-3)=3x+x=12 equation:



4x+2(x-3)=3x+x=12
We move all terms to the left:
4x+2(x-3)-(3x+x)=0
We add all the numbers together, and all the variables
4x+2(x-3)-(+4x)=0
We multiply parentheses
4x+2x-(+4x)-6=0
We get rid of parentheses
4x+2x-4x-6=0
We add all the numbers together, and all the variables
2x-6=0
We move all terms containing x to the left, all other terms to the right
2x=6
x=6/2
x=3

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