4x+2(x-4)=4(x-1)+x

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Solution for 4x+2(x-4)=4(x-1)+x equation: 



4x+2(x-4)=4(x-1)+x

We move all terms to the left:

4x+2(x-4)-(4(x-1)+x)=0

We multiply parentheses

4x+2x-(4(x-1)+x)-8=0



We calculate terms in parentheses: -(4(x-1)+x), so:

4(x-1)+x

We add all the numbers together, and all the variables

x+4(x-1)

We multiply parentheses

x+4x-4

We add all the numbers together, and all the variables

5x-4

Back to the equation:

-(5x-4)



We add all the numbers together, and all the variables

6x-(5x-4)-8=0

We get rid of parentheses

6x-5x+4-8=0

We add all the numbers together, and all the variables

x-4=0

We move all terms containing x to the left, all other terms to the right

x=4

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