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4x+2(x-4)=4(x-2)+x
We move all terms to the left:
4x+2(x-4)-(4(x-2)+x)=0
We multiply parentheses
4x+2x-(4(x-2)+x)-8=0
We calculate terms in parentheses: -(4(x-2)+x), so:We add all the numbers together, and all the variables
4(x-2)+x
We add all the numbers together, and all the variables
x+4(x-2)
We multiply parentheses
x+4x-8
We add all the numbers together, and all the variables
5x-8
Back to the equation:
-(5x-8)
6x-(5x-8)-8=0
We get rid of parentheses
6x-5x+8-8=0
We add all the numbers together, and all the variables
x=0
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