4x+2-3(2-x)=3(x-1)

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Solution for 4x+2-3(2-x)=3(x-1) equation: 



4x+2-3(2-x)=3(x-1)

We move all terms to the left:

4x+2-3(2-x)-(3(x-1))=0

We add all the numbers together, and all the variables

4x-3(-1x+2)-(3(x-1))+2=0

We multiply parentheses

4x+3x-(3(x-1))-6+2=0



We calculate terms in parentheses: -(3(x-1)), so:

3(x-1)

We multiply parentheses

3x-3

Back to the equation:

-(3x-3)



We add all the numbers together, and all the variables

7x-(3x-3)-4=0

We get rid of parentheses

7x-3x+3-4=0

We add all the numbers together, and all the variables

4x-1=0

We move all terms containing x to the left, all other terms to the right

4x=1

x=1/4

x=1/4

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