4x+2-3(x-4)=19(x-4)

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Solution for 4x+2-3(x-4)=19(x-4) equation: 



4x+2-3(x-4)=19(x-4)

We move all terms to the left:

4x+2-3(x-4)-(19(x-4))=0

We multiply parentheses

4x-3x-(19(x-4))+12+2=0



We calculate terms in parentheses: -(19(x-4)), so:

19(x-4)

We multiply parentheses

19x-76

Back to the equation:

-(19x-76)



We add all the numbers together, and all the variables

x-(19x-76)+14=0

We get rid of parentheses

x-19x+76+14=0

We add all the numbers together, and all the variables

-18x+90=0

We move all terms containing x to the left, all other terms to the right

-18x=-90

x=-90/-18

x=+5

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