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4x+2-x=3(x+1/2x)
We move all terms to the left:
4x+2-x-(3(x+1/2x))=0
Domain of the equation: 2x))!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
4x-x-(3(+x+1/2x))+2=0
We add all the numbers together, and all the variables
3x-(3(+x+1/2x))+2=0
We multiply all the terms by the denominator
3x*2x))-(3(+x+2*2x))+1=0
We add all the numbers together, and all the variables
x+3x*2x))-(3(+2*2x))+1=0
Wy multiply elements
6x^2+x+4x=0
We add all the numbers together, and all the variables
6x^2+5x=0
a = 6; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·6·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*6}=\frac{-10}{12} =-5/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*6}=\frac{0}{12} =0 $
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