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4x+2/3(6x-9)=4(x+1)
We move all terms to the left:
4x+2/3(6x-9)-(4(x+1))=0
Domain of the equation: 3(6x-9)!=0We multiply all the terms by the denominator
x∈R
4x*3(6x-9)-((4(x+1)))*3(6x-9)+2=0
We calculate terms in parentheses: -((4(x+1)))*3(6x-9), so:Wy multiply elements
(4(x+1)))*3(6x-9
12x^2(6-((4(x+1)))*3(6x-9)+2=0
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