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4x+2/5x-6=1
We move all terms to the left:
4x+2/5x-6-(1)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
4x+2/5x-7=0
We multiply all the terms by the denominator
4x*5x-7*5x+2=0
Wy multiply elements
20x^2-35x+2=0
a = 20; b = -35; c = +2;
Δ = b2-4ac
Δ = -352-4·20·2
Δ = 1065
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-\sqrt{1065}}{2*20}=\frac{35-\sqrt{1065}}{40} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+\sqrt{1065}}{2*20}=\frac{35+\sqrt{1065}}{40} $
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