4x+20+4x+12=128

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Solution for 4x+20+4x+12=128 equation: 



4x+20+4x+12=128

We move all terms to the left:

4x+20+4x+12-(128)=0

We add all the numbers together, and all the variables

8x-96=0

We move all terms containing x to the left, all other terms to the right

8x=96

x=96/8

x=12

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