4x+20=3(x+2)-19

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Solution for 4x+20=3(x+2)-19 equation: 



4x+20=3(x+2)-19

We move all terms to the left:

4x+20-(3(x+2)-19)=0



We calculate terms in parentheses: -(3(x+2)-19), so:

3(x+2)-19

We multiply parentheses

3x+6-19

We add all the numbers together, and all the variables

3x-13

Back to the equation:

-(3x-13)



We get rid of parentheses

4x-3x+13+20=0

We add all the numbers together, and all the variables

x+33=0

We move all terms containing x to the left, all other terms to the right

x=-33

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