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4x+28=4(x+3)+
We move all terms to the left:
4x+28-(4(x+3)+)=0
We calculate terms in parentheses: -(4(x+3)+), so:We get rid of parentheses
4(x+3)+
We add all the numbers together, and all the variables
4(x+3)
We multiply parentheses
4x+12
Back to the equation:
-(4x+12)
4x-4x-12+28=0
We add all the numbers together, and all the variables
16!=0
There is no solution for this equation
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