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4x+2=1/2x+12
We move all terms to the left:
4x+2-(1/2x+12)=0
Domain of the equation: 2x+12)!=0We get rid of parentheses
x∈R
4x-1/2x-12+2=0
We multiply all the terms by the denominator
4x*2x-12*2x+2*2x-1=0
Wy multiply elements
8x^2-24x+4x-1=0
We add all the numbers together, and all the variables
8x^2-20x-1=0
a = 8; b = -20; c = -1;
Δ = b2-4ac
Δ = -202-4·8·(-1)
Δ = 432
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{432}=\sqrt{144*3}=\sqrt{144}*\sqrt{3}=12\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-12\sqrt{3}}{2*8}=\frac{20-12\sqrt{3}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+12\sqrt{3}}{2*8}=\frac{20+12\sqrt{3}}{16} $
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