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4x+2=1/2x+5
We move all terms to the left:
4x+2-(1/2x+5)=0
Domain of the equation: 2x+5)!=0We get rid of parentheses
x∈R
4x-1/2x-5+2=0
We multiply all the terms by the denominator
4x*2x-5*2x+2*2x-1=0
Wy multiply elements
8x^2-10x+4x-1=0
We add all the numbers together, and all the variables
8x^2-6x-1=0
a = 8; b = -6; c = -1;
Δ = b2-4ac
Δ = -62-4·8·(-1)
Δ = 68
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{68}=\sqrt{4*17}=\sqrt{4}*\sqrt{17}=2\sqrt{17}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{17}}{2*8}=\frac{6-2\sqrt{17}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{17}}{2*8}=\frac{6+2\sqrt{17}}{16} $
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