4x+2x+22-48=3(x+72)

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Solution for 4x+2x+22-48=3(x+72) equation: 



4x+2x+22-48=3(x+72)

We move all terms to the left:

4x+2x+22-48-(3(x+72))=0

We add all the numbers together, and all the variables

6x-(3(x+72))-26=0



We calculate terms in parentheses: -(3(x+72)), so:

3(x+72)

We multiply parentheses

3x+216

Back to the equation:

-(3x+216)



We get rid of parentheses

6x-3x-216-26=0

We add all the numbers together, and all the variables

3x-242=0

We move all terms containing x to the left, all other terms to the right

3x=242

x=242/3

x=80+2/3

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