4x+2x-8=2(x-2)

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Solution for 4x+2x-8=2(x-2) equation: 



4x+2x-8=2(x-2)

We move all terms to the left:

4x+2x-8-(2(x-2))=0

We add all the numbers together, and all the variables

6x-(2(x-2))-8=0



We calculate terms in parentheses: -(2(x-2)), so:

2(x-2)

We multiply parentheses

2x-4

Back to the equation:

-(2x-4)



We get rid of parentheses

6x-2x+4-8=0

We add all the numbers together, and all the variables

4x-4=0

We move all terms containing x to the left, all other terms to the right

4x=4

x=4/4

x=1

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