4x+3(4x-2)=3(x+1)

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Solution for 4x+3(4x-2)=3(x+1) equation: 



4x+3(4x-2)=3(x+1)

We move all terms to the left:

4x+3(4x-2)-(3(x+1))=0

We multiply parentheses

4x+12x-(3(x+1))-6=0



We calculate terms in parentheses: -(3(x+1)), so:

3(x+1)

We multiply parentheses

3x+3

Back to the equation:

-(3x+3)



We add all the numbers together, and all the variables

16x-(3x+3)-6=0

We get rid of parentheses

16x-3x-3-6=0

We add all the numbers together, and all the variables

13x-9=0

We move all terms containing x to the left, all other terms to the right

13x=9

x=9/13

x=9/13

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