4x+3(4x-20)=68

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Solution for 4x+3(4x-20)=68 equation: 



4x+3(4x-20)=68

We move all terms to the left:

4x+3(4x-20)-(68)=0

We multiply parentheses

4x+12x-60-68=0

We add all the numbers together, and all the variables

16x-128=0

We move all terms containing x to the left, all other terms to the right

16x=128

x=128/16

x=8

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